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Criteria for Selection
Torsion Moments
Installation and Maintenance
Criteria for selection of joints
The tables give the maximum allowable torque (expressed in Kgm) calculated on the basis
with an angle of inclination of 10° and continuous use.
If the inclination angle is over 10° the values shown will be reduced in accordance
with the torque factors shown below.
ANGLE a ANGLE F
5° 1,25
10° 1
20° 0,75
30° 0,45
40° 0,43
Example: criteria for selection of joint after taking into account the power to be transmitted,
the speed and the angle of inclination.

Example:
- power N 3 CV
- speed n 2000 giri/min.
- angle a 20°

The corresponding torque moment is:
716,2 x N 716,2 x 3
Mt =
=
= 1,074 Kgm
n 2000
The torque to be transmitted is 1074 Kgm but since the joint angle is 20° one must select a joint
of larger dimension and torque carrying capacity to compensate.
Since the torque factor for 20° is 0,75 (as indicated on the table) one divedes the Mt by F.
MT 1,074
=
MT 1,432 Kgm
F 0,75

The appropriate joint should have a torque capability of 1432 Kgm or greater which is selected
from the table of joint with needle bearings is type 105V.

Pay attention that 1 Kgm = 9,80665 Nm